Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 145
DE = DU + DL. LE, (II. 3). 8—2 116 EXERCISES ON ECCLID [155. Therefore SL . LU + DL2 = DL2 + DL . LE, and therefore SL. LH = DL. LE which proves one part of theproposition. Again BE. DII = DE. HL + DE. DL, (II. 1), and DII. DE = DIP + DR. HE, (II. 3). Therefore DH2 -hDH.HE = DE. ILL + DE. DL, but… … base angles, then shall AB be equal to AC. About the triangle AEC describe a circle meeting AF produced m 0. The circle about the triangle ABD must also pass through 0.For, if possible, let it meet AF in 0 and join OB, OE, OD, OC,OB and OD. Because the chords CE, BD are equal and subtend the…
Geometry
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