Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 211
0 bethe centre of the system of points in involution. Therefore OA . OA = OB . OS = OC. OC (hyp.), but sinceOA . OA = OB. OB, therefore 0 is a point on the radical axis ofthe circles L and 31. Similarly 0 lies on the radical axes of M andN and of N and L; therefore 0 is the radical centre of the… … meet its sides and diagonals in A, A\ B, B\ C} C. Then shallthese six points be in involution. Join C, the point of sectionon either diagonal, with the vertices of the opposite angles, Pand R. 213.] AND IN MODERN GEOMETRY. 183 {P. ABCC) = {P. QSOC} = {R. QSOC} = {R. BAGC}. But {R . BACG} = {R .…
Geometry
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