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Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)

McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 34

An illustration from Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students, 1881, leaf 34
icularfrom the centre of its circumscribed circle on any side is doublethe corresponding perpendicular in the other triangle. Def. Sides of equiangular triangles opposite equalangles are called corresponding (or homologous) sides, andlines similarly drawn in similar figures are called… … Because HK joins the middle points of two sides of the tri-angle BOG, HK is parallelto BC and equal to half of BC, therefore the angleOHK is equal to OBC. Inlike manner the side HGis half of AB and parallelto it, therefore the angleGHO is equal to ABO, andtherefore the angles GHKand ABC are equal.…

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