Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 89
the diameter of the circumscribing circle (VI. C). Let ABC be the given triangle. AD the perpendicular, and AEa diameter of the circumscribingcircle. Produce EA until AF equalsAD, and BA until AG equals AC.Join FQ, BE and EC. The angle ACE in a semicircleis a right angle (III. 31), andtherefore… … 93.] AND IN MODERN GEOMETRY. 61 angles DAC and FAG are equal in all respects (I. 4), therefore,since ADC is a right angle, AFG is a right angle, but FBA in asemicircle is also right, therefore the four points F, B, F, G are inthe same circumference (51), and therefore (III. 35), BA.AG = FA.AF,that…
Geometry
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![An illustration from Nicolai Copernici Torinensis De reuolutionibus orbium coelestium, libri VI : Habes in hoc opere iam recens nato, & aedito, studiose lector, motus stellarum, tam fixarum, quàm erraticarum, cum ex ueteribus, tum etiam ex recentibus obseruationibus restitutos: & nouis insuper ac admirabilibus hypothesibus ornatos. Habes etiam tabulas expeditissimas, ex quibus eosdem ad quoduis tempus quàm facillime caculare poteris. Igitur eme, lege, fruere. [Line in Greek] (1543)](https://img.insideoutlibrary.com/img/200/ia-nicolaicopernici00cope-351-242.webp)
