[Coffin, John Huntington Crane], 1815-1890. [from old catalog] · New York, D. Van Nostrand · leaf 124
d azimuth of aheavenly body at a given place and time. Solution. Find the decimation of the body and its hour-angle at the given time. (Probs. 21, 34, and 35.) Then in the spherical triangle PMZ (Fig- 24), we have given PZ = : 90°- -L, PM = 90°- -d, ZPM = *, to find ZM = 90°- -A, PZM = Z. By… … which, by substituting the corresponding parts of the trian-gle P Z M, give tan 6 = cot d cos £, . , (sm (p + L) sin d sin h — - , cos (j) cotZ=cos(^+Z)coU, sm 0 (96) J 118 NAVIGATION. If we put 0 = 90°—</>, these becometan 0 == tan d sec t, sin h (cos (f)r—L) sin dsin </ , ~ sin (0—Z) cot…
Navigation · Nautical astronomy
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