[Coffin, John Huntington Crane], 1815-1890. [from old catalog] · New York, D. Van Nostrand · leaf 246
en h = 90°- Z M, d = 90°- P M = 90°- P M, A=90°-ZM, * = MPM, to find from the several triangles of Fig. 44, the latitude,Z=90°-PZ.Various solutions of this problem have been given, fromwhich the following are selected. 240. (A.) 1st Method hi BowdiicNs Navigator. Let T (Fig. 44), be the middle… … of T. Fig. 44. 240 NAVIGATION. AsPTM and PTM are equal right triangles, we have theangle PTM = PT W= 90°, 2 = 90°- Z T M = Z TM— 90°,and J« = MPT = MPT. 1. In the right triangle PTM, by Sph. Trig. (80), (84),and (82), sin A = cos d sin -J- Z,) / ^ x sin B = sin d sec JLy )or tan B == tan c? sec -J…
Navigation · Nautical astronomy
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