Structural analysis and design of airplanes (1920)
United States. Army. Air Corps · [Washington] · leaf 26
of joints.(10 and 11) v6-=2he ; v5 = 2h5 (12) 2V = v6 + v5 —1000 = 0 (13) or 2h6 + 2h5—1000 = 0 (14) 2H = h6 + 600 — 400 — h5 = 0 Solving equations 13 and 14 simultaneously. h6 = +150andh5 = —350v6 = +300 and v5 = +700 Stress in \± u2 = —Vl502 + 3002^—336 lbs. compression —789 lbs. compression u2l2… … 600w D /OOO <?oo / Bilk l D 700 Fig. 7. Joint U2 Fig. 8. Truss to Rightof Section D—D 11. Free Body Method—It will be observed that in the solution justgiven the method employed in each case was the isolation of the struc-ture, in whole or in part, with all the external loads acting upon it,…
Airplanes
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