Manning, Henry Parker, 1859- · Boston, U.S.A., Ginn & Company · leaf 44
Draw MN perpendicular to CF at its middle point andrevolve the figure about MN as an axis. CD will fall uponthe original position of AB, and AB will fall upon the originalposition of CD. Therefore, CD is parallel to AB. Corollary. FB and CD are both parallel to MN.F … Proof. FB and CD are symmetrically situated with respectto MN, and cannot intersect MN since they do not intersecteach other. Draw FH to H, on CD, intersecting MN in K.If H move off indefinitely on CD, FH will approach the posi-tion of FB as a limit. Now K cannot move off indefinitelybefore H does,…
Geometry, Non-Euclidean
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