Manning, Henry Parker, 1859- · Boston, U.S.A., Ginn & Company · leaf 45
position at a 34 NON-EUCLIDEAN GEOMETRY finite distance on MN; for FB, and therefore CD, -would thenintersect MN and each other at this point. Therefore, H andK must move off together, and the limiting position of FHmust be at the same time parallel to CD and MN. In the same way we can prove that… … First, when they are all in the same plane. Let AB and EF be parallel to CD, to prove that they areparallel to each other. Proof. Suppose AB lies between the other two. To H, anypoint on CD, draw AH and EH, and let K be the point whereEH intersects AB. As H moves off indefinitely on CD, Alland EH…
Geometry, Non-Euclidean
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