Hatton, Richard G · London, Chapman & Hall ld. · leaf 284
do A; weonly have M above it. But we can find M on the Solving Problems 249 ground by drawing from A a line under IM. IMvanishes at 30° left, so AM must vanish there too, not toV.P.i. A line being thus drawn from A to V.P. 30, anda vertical dropped from M, we get M. Just as A isrelated to E and E… … 1/B2 Fig. 190.—The junction found by the V.P.s of the lines of junction. junction. This is done in Fig. 190. We arrive at themethod as follows: IM vanishes at V.P. 30. AX isunder IM; it is in the same vertical plane, therefore theV.P. of AX will be on the same vertical V.L. as IM.Now, the V.P. of…
Perspective · Drawing
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