Hatton, Richard G · London, Chapman & Hall ld. · leaf 294
Fia. 201.—Diagram Q. 9. In the solution of this question we first find V.P. of Solving Problems 259 AB, the front edge of base of cross. Then we bring BAforward by means of this V.P.i until we can cut it off inC under C. Through C we make our G.L. FindingM.P.1, we find A^ and B on the ground-line,… … Fig. 202.—The-cross restored. set off BD equal to AC, and obtain E, which, whenthrown up, meets the lines from G- and 0, and completesthe left arm of the cross. The under side of this newarm vanishes to V.P.2. The top is made by continuingthe line of height OG to H, making GH equal to AC. I 260…
Perspective · Drawing
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