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An elementary treatise on modern pure geometry (1893)

Lachlan, Robert · London, New York, Macmillan and Co. · leaf 97

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GA are equal. Hence 12 is one of the Brocard points (§ 116). Similarly we may show that AB, BG, GA intersect on theBrocard circle in the other Brocard point. Hence if 11 and fi he the Brocard points, defined as in § 116,and if AD., Bil, GO, cut BD!, GO,, Afl respectively in the pointsU, A, B, the… … Let the symmedian lines AK, BK, GK be produced to meetthe circumcircle of the triangle ABC in the points P, Q, R. Thensince SA is perpendicular to AK, it follows that A is the middlepoint of AP 135. Ex. 1. Show that Brocards first triaDgle is similar to the triangleABC. Ex. 2. Show that if KA, KB,…

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