Exercises on Euclid and in modern geometry for the use of schools, private students, and junior university students (1881)
McDowell, James L · Cambridge, Deighton, Bell, and Co. · leaf 252
andED, ED in the internal centre of similitude. Join AD, ED, andproduce these lines to meet in C, and let DD meet AB in 0. Because the transversal DO meets the sides of the triangleACE, therefore (167) (AD : Z>C| [CD : DEjy but CD and CD are tangents to the circle EDE since it cuts theother two… … In the same manner it can be proved that EE passes through0, and that ED and ED intersect in K the internal centre ofsimilitude of the given circles. Again, because from the point 0 two secants OD and OE aredrawn meeting the circle EDE\ therefore (241) K is a point onthe polar of 0 with respect to…
Geometry
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