A hand book of general instruction for mechanics, containing useful rules and memoranda for practical men (1907)
Smith, Franklin Elijah, 1872- · New York, D. Van Nostrand company · leaf 242
Fig. 46 CIRCULAR MEASURE 229 3.14163 half sum of diameters 9.4248 = circumference 12 113.0976 sq. in. Ans. Circular Areas Example. Find the area of metal in a ring whose outerdiameter is 13 inchesand inner diameter 9inches. (Fig. 47.) First find the areaof the outer diameter.Next find the area… … ± Fig. -.7 Thus 13 X 13 X .7854 = 132.7326, area of large diameter,and 9 X 9 X .7854 = 63.6174, area of small diameter.Difference, 69.1152, area of metal. Example. What area of metal is there in a section 3 inchesin diameter? (Fig. 48.)
Mechanics · Arithmetic · Measurement
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