Machinists' and draftsmen's handbook, containing tables, rules and formulas, with numerous examples explaining the principles of mathematics and mechanics as applied to the mechanical trades; intended as a reference book for all interested in mechanical work (1910)
Lobben, Peder, 1858- · New York, D. Van Nostrand company · leaf 314
and lower half of the beam is equal;consequently, when calculating moment.of inertia for a surfacelike Figs. 8 and 7, it is only nec-essary to calculate the momentof inertia for half the beam,and multiply by 2 in order to e X —: get the moment of the whole beam. Solution: a = 3 X )4 X (2K)2 =… … for upper half,for lower half. Moment of inertia = 43.125 for beam (approximately).Area of cross-section of beam is 10 square inches. Radius of gyration = \ * ° = 2.07 inches.&J \ 10 Example 3. Find approximately the moment of inertia of a surface, asFig. 9 (usual section for cast-iron beams),…
Mechanical engineering
Internet Archive · Library of Congress · Public Domain Mark 1.0. Free to use for anything.
