en thesupports 14 feet, then, by Mr. Hodgkinsons formula, we have 26 x4-06 X 13-25168 = 832 tons = the breaking weight in the Fig. 2. A middle. But assuming that the same quantity of metal was run into the form of greatest strength, as at A, fig. 2, we shall then have an area for the bottom flange… … g^^-t^^j^^^ ...w^ 5. v^;.;, .„,.^A .^q;^ ^ ^ The following woodcut (fig. 5) exhibits a longitudinal sectionof portions of the basement and first stories of the mill, withsections of the iron beams and arches. The arches E, E, E, Fig. 5.
Building, Iron and steel
Internet Archive · University of Toronto, Robarts Library · Public Domain Mark 1.0. Free to use for anything.
