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Practical stationary engineering : in form of questions and answers (1909)

West, Andrew Cassius, 1855- · Boston, Mass. : A.C. West · leaf 92

An illustration from Practical stationary engineering : in form of questions and answers, 1909, leaf 92
5 2 = constant.1.1250 1.125)4.8125(4.274500 31252250 8750 7875 4.27 875 1 to be added.5^27 .6875 = diameter of rivet hole.5.27 = sum. 481251375034375 3.623125 = pitch of rivet 3f inches. How is the diameter of a rivet hole found for a single-rivetedand double-riveted lap joint? Diameter equals… … C>-^-

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