The steam engine and turbine; a text-book for engineering colleges (1911)
Heck, Robert Culbertson Hays, 1870- · New York, D. Van Nostrand company · leaf 352
. (172), or Fi = F0[ cos a + j cos 2 a )■ As to F2 and F3, their resultant Fb = ^3 — F2 (see Fig. 157) is thefree counterforce whose horizontal component partly balances F\.This component is H = Fb cos a. By subtraction, we get the horizontal shaking force to beSn = (F0 — Fb) cos a + j F0 cos 2 a.… … Fig. 191. — Shaking-force Components. the radius of the circle to (F0 — Fb) without changing the distance ofpoints on the curve EiE2 from the line GH. Thus, in Fig. 191 I, thediagram on AB is drawn with F0 as radius, and gives F\\ which wouldbe identical with >Sh if M3 were made equivalent to…
Steam-engines · Steam-turbines
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