nal between AO and AD. So that to find BO~AD-AO the surface of rupture, when d is known, AO V: we draw BO, making the angle a + d AD-a/AD.AO AD with the normal to the natural slope; AD-AO AO then we lay off AI=a/AO.AD, and from 1- AD I draw the line IC || OB to C; whence AC is the surface of… … Fig. 5. BAO=90-(w+(p)+a + io=90-(cp-d) In Fig. 5, angle ABO = cp— a + a + d = q) + d, whence, BO=cos(cp-a) AO_sin(<p + c?) AB_sin(^— e) COS(a-\-d) AB— cos(a + c?)' AD~"cos(a— e) Substituting these values of BO and n in that for CI, and this in value for E, Multiplying these two equations to-…
Engineering
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