Hatfield, Robert Griffith, 1815-1879. [from old catalog] · New York & London, Wiley and Putnam · leaf 48
he other at g ; join g and e ; upon / and g, with d b and a b for radius, describe arcs intersecting at h ; join g and h, also k and/; then Fig. 66 will every way equal Fig. 65. So, right-lined figures of any number of sides may be copied,by first dividing them into triangles, and then proceeding… … Fig. 67. 101.— To make a parallelogram equal to a given triangle. Let a b c, {Fig. 67,) be the given triangle. From a, draw a d, at right angles to b c; bisect a d in e; through e, draw f g, parallel to & c ; from b and c, draw b f and c g, parallel to d e ; then bfg c will be a parallelogram…
Carpentry · Architecture
Internet Archive · Library of Congress · Public Domain Mark 1.0. Free to use for anything.
![An illustration from Divina proportione : opera a tutti glingegni perspicaci e curiosi necessaria oue ciascun studioso di philosophia: prospettiua pictura sculptura: architectura: musica: e altre mathematice: suavissima: sotile: e admirabile doctrina consequira: e delecterassi: co[n] varie questione de secretissima scientia (1509)](https://img.insideoutlibrary.com/img/200/ia-divinaproportion00paci-84-119.webp)
