International Library of Technology · Scranton, International Textbook Co. · leaf 152
t the distant end will be 20,000 feet; hence,and R = 20 X .9972 = 19.944, 1,000 X 19.944 - 10 X 1,6421,000 + 10 = 3.4891. Hence the distance of the fault from the testing station must be3.4891 .9972 X 1,000 = 3,498.9 ft. Ans. 42. Locating a Partial Ground Without an Avail-able Good Wire.—The… … incorrect result. However, it is about the only way wherethere is no available good wire and when the tests must bemade from one end only. The normal resistance of theline must be known from some previous measurement,unless it can be calculated from the length and size of the 15 ELECTRIC…
Electrical engineering
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