S2 SHEAR DIAGRAM Simple Beam with Uniformly Distribu-ted Load over Entire Length and OneConcentrated Load 90 STEEL CONSTRUCTION Therefore 11 = 250,00020 = 12,500 # Rt = 20,000 - 12,500 = 7500 #Maximum shear is 12,500#. Zero shear occurs under theload P. Hence this is the point of maximum bending… … SHEAR DIAGRAM Fig. 83. Simple Beam with Two Rates of Uniformly Distributed Load Two Uniformly Distributed Loach Not Overlapping. Fig. 83illustrates a beam with one uniformly distributed load for part of itslength and another load for the remainder, as shown. The total loadon the beam is Uy< m=:…
Building, Iron and steel · Steel, Structural · Theses
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