International Library of Technology · Scranton, International Textbook Co. · leaf 244
tion.—1. If the inductance L = .25 henry, the reactance2iv n L = 2 X 3.14 X 60 X -35 = 94.2 ohms. The capacity y = 20 microfarads, hence the capacity J^ reactance lOi II tfe) 1,000,000 2 7rn/ 2 X 3. 14 X 60 X 20 132.7 ohms. The E. M. F. necessary to overcome resistance — C J^ =5 X 100 = 500 volts =… … Scale J =250 Volts. Fig. 1485. 2. Since the E. M. F. necessary to overcome capacity is663.5 volts and is 90° behind the current, while that to over-come self-inductance is only 471 volts and 90° ahead of thecurrent, the resultant component at right angles to the ^ = 471 - 663.5 = - 192.5, and is…
Electrical engineering
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