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Plane and solid geometry (1908)

Gore, James Howard, 1856-1939 · New York, Longmans, Green, and co. · leaf 153

An illustration from Plane and solid geometry, 1908, leaf 153
. To prove that area ABC > area ABC. Draw AD perpendicular to BC. Then since (by 52) the oblique line AB is greater than theperpendicular AD, we have AB > AD. But AB and AD are the altitudes of the triangles ABC andABC, and as they have the same base, that triangle is thegreater which has the… … Let ABC and ABC be two isoperimetric triangles havingthe same base BC, and let the triangle ABC be isosceles. To prove that area ABC > area ABC. Produce AB to D, making AD = AB, and draw CD. Since B, C, and D are equally distant from A, a circle withA as a centre could be drawn through B, C, and…

Geometry

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