A hand book of general instruction for mechanics, containing useful rules and memoranda for practical men (1907)
Smith, Franklin Elijah, 1872- · New York, D. Van Nostrand company · leaf 280
ever the shorterarm (in this case the distance from the fulcrum to weight)bears the greater weight, it is very clearly seen that theshare of the whole weight supported at A must be 2f tons,because 4 — 1J ■= 2f. Example. A beam 19 feet long and weighing 700pounds is resting on two supports A and B,… … Fig. 81 First find the share each support bears of weight 1. weight of weight 1, supported 6X8 48 _ = — = 2.63 tons 19 19 at A. Then as A supports 2.63 tons of the weight 1, B mustsupport 5.37 tons of the weight 1. In the same manner find the share each support bearsof weight 2. 6X4 24 = — =. 1.27…
Mechanics · Arithmetic · Measurement
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